Yes the phase shift is always to the right otherwise you run the problem of mixing up sine versus cosine and negatives and positives. If you look at shifting the graph pi/2 to the left you'll notice the cosine graph starts at the bottom this indicates it will be a negative equation.
Mashallah you're smartOkay sweety. So from trough to trough or from peak to peak you agree the period is 2pi?
From -pi/4 to pi/4 you agree that is a distance of pi, right?
Since cos starts either at the top of the peak or at the bottom of the trough and your graph has at the origin a cosine graph that's inbetween trough and peak you have a phase shift of pi/2.
One more thing, I believe you need a negative at the beginning of your equation. Hope I helped dear.
yh thats right and if it starts at 1 its positive,im taking this same thing right now in my mathematical methods class.
I'm learned not smartMashallah you're smart
Anyone can learn if they try hard enough.
Ok so the phase shift is always to the right? That helps a lot then. Thank you abaayo.
it should start at -pi/2 and end at 3p/2. the horizantal shift is a shift to the left, so not sure why it would be wrong.
No problem abaayo. feel free to DM me if you have any questions.
I agree you can do a left phase shift to make the graph a positive and not negative cosine.
no problem. what level of physics is this?Thanks darling
Physics II. I'm currently on magnetism and faraday's laws
They were asking for when the a value was less than 0.
Naw, I finished calculus in highschool haven't taken any calculus in Uni.So you're taking all the hard sciences and calculus
When is your exam for the trig/pre-calc graphs?
My final exam is on tuesday
Good luck abaayo, allah ha ku barakaayo Insha allah. Look over videos and study hard but don't study too much the night before. make sure to exercise and eat healthy. May you do well and may God guide you to study well every day leading up to the exam, ameen.
i din't remember that stuff.
