Yeah, same. I can't stand most of applied mathematics. The pure is the shit!
You're third/fourth year I'm guessing? What areas are you mostly interested?
I've finished my undergraduate studies, which were almost exclusively pure in the third/fourth year!
I started my second year a couple weeks ago. At the moment I'm most interested in group theory which we started last year. In a few months we'll be doing a course which includes rings and modules which I'm looking forward to. We did a course on metric and topological spaces last year which was pretty cool.
What about you? I'd love some recommendations if you're in 3rd or 4th year
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Can you help a brother out? I just want to know how they went from 3.3=log(I/Io) to 10^3.3=(I/Io)
I am a girl lmao i just say that a lotHelp a brother out ? I thought you were a girl
Anyways, there is a formula Y = Log base a * X. So when they say 3.3 = Log(1/10) all you do is use change of base formula which would be from Y = Log base a * X --> a^Y = x.
Therefore, your final solution will be 10^3.3 = 1/10 since 10 is the base of Log by default.
Feel free to ask more questions.
I am a girl lmao i just say that a lot
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I don't understand what my teacher did here too
But what about the variable that the 63 is being divided by?All your teacher did was move 80 from left hand side to right hand side and he just computed the equation on the left hand side, so i'm guessing when you try punching it into your calculator it doesn't show the correct answer but try 10 * log (63) + 80. Should give you 97.99 which is approximately 98
But what about the variable that the 63 is being divided by?
The carbon you labelled 7 has a hydroxyl, hydrogen and ch3 attached to it , meaning the longest chain has 8 carbon atoms. The hydroxyl group is on the second carbon atom and the methyl group is on the 4 carbon atom.View attachment 46863 is anyone knowledgeable in organic chemistry? I'm having troubles with 70 c) the answer booklet says it's 4-methyloctan-2-ol but I got 2,4-dimethylheptan-1-ol.