SSpot Beefs

[Boqor]

Imam Tawhidi (may Allah preserve him and bless him with a polygamous marriage) is such a BOSS that he almost converted me to the manhaj of ahlul bayt. To the name of Hassan and Hussein I would add Tawhidi as I whip myself senselessly in public and sob violently for the martyrs of Karbala.

Only a deviant would be against a sheikh named after tawhid. Admit it sxb: you're a mushrik. And a trinitarian one at that.

Remember your guru Ibn Taymiyyah died in prison so Imam Tawhidi's popularity is proof of nothing. If your boys wanna throw down in the mean streets of Sydney though, the imam has a standing offer to meet them any where, any time. Don't make excuses now habibi:

Even rafidah don't claim this guy, he's a complete mess when I first heard him waffling I thought it was an akhi doing a parody on gaal booty clapping secular Muslims like you.

Put some respect on ibn taymiyyahs name may Allah grant him jannah, the fact you know his name but not the name of the other pussy ass scholars around him at the time attests to his truthfulness, the legends live in our hearts while the cowards are lost in history.

 

[Bidaar Wanagsan]

Boqor

What does that signify? It signifies that many Sunni Muslims are a bunch of violent terrorists? This man criticise the Saudi/Wahhabism interpretations of Islam and yet, he can’t freely walk in certain areas of Sydney without security escort. A bunch of savages.

Tawhidi is a pious man, but he's built like a kickboxing champion. He would wreck any Saudi wannabe who took him on and shave the pubic hair on their chin, but these cowards like to swarm their targets in mob fashion. No wonder @Boqor approves. It's the only way he's ever survived in the hood.

 

[Bidaar Wanagsan]

Even rafidah don't claim this guy, he's a complete mess when I first heard him waffling I thought it was an akhi doing a parody on gaal booty clapping secular Muslims like you.

Put some respect on ibn taymiyyahs name may Allah grant him jannah, the fact you know his name but not the name of the other pussy ass scholars around him at the time attests to his truthfulness, the legends live in our hearts while the cowards are lost in history.

Interesting that you dodged the Tawhidi challenge. All talk and no action. Typical keyboard jihadist.

I know that Tawhidi is not a fangirl of the Iranian mullahs. He's a critic of theocratic dog rapers no matter whether they are Sunnis or Shias. So of course the Khomeinist lowlifes attack him. All great men stand above the sectarian fray. They're independents. Imam Tawhidi, like Imam Wanagsan, is a mujtahid.

 

[Bidaar Wanagsan]

@Boqor

I thought you liked the caliphate. It was the Abbasid caliphate that clapped Ibn Taymiyyah in jail. First the ulema of Syria, and then the ulema of Egypt said "this crook needs to go" and poor old Taymiyyah was raped by multiple felons. No other figure in the history of Islamic theology has been to prison as many times.

He was not a sheikh. He was a jailbird. The convicts liked him though. You still haven't answered my challenge of why Ibn Tay said you can have sex with a melon.

 

[CangeeroBear]

Go for it. But be careful. You might fully switch to maths after you see the solution in its full glory!

This is crazy, ok so it took me a while to even begin to attack this.I havent solved it but this is the way i think i can hit it
1. Trig identity to change into two Cos integrals
2.Relate your integrals to gaussian integration whereby get it in the form e^-x^2
3. If you use substitution you would need to do integration by parts
4. Use gaussian integration property that integration of e^-x^2 to infinite limits is Pi.

 

[Naissur]

This is crazy, ok so it took me a while to even begin to attack this.I havent solved it but this is the way i think i can hit it
1. Trig identity to change into two Cos integrals
2.Relate your integrals to gaussian integration whereby get it in the form e^-x^2
3. If you use substitution you would need to do integration by parts
4. Use gaussian integration property that integration of e^-x^2 to infinite limits is Pi.

You're absolutely on the right track! Your intuition is very impressive! I think I can say the following without giving anything away. You can use the standard results of ∫e^(-x^2), ∫cos(x^2) and ∫sin(x^2) over [0, ∞) without proof of course (since they are baby stuff compared to this). By parts might not be useful, though. This is ridiculously hard, but you're a single observation away from making a significant progress on it.

 

[CangeeroBear]

You're absolutely on the right track! Your intuition is very impressive! I think I can say the following without giving anything away. You can use the standard results of ∫e^(-x^2), ∫cos(x^2) and ∫sin(x^2) over [0, ∞) without proof of course (since they are baby stuff compared to this). By parts might not be useful, though.

I have only done 2 calculus units so I’m a bit slow with this.I was thinking using substitution to get a gamma function but after I get an integral Of e^(ax^2+bx^-2), This is I think is the last barrier.So either gamma function, polar coordinates or Cartesian coordinates.All seem horrendous but I’ll see if I can get a solution.

 

[Naissur]

I have only done 2 calculus units so I’m a bit slow with this.I was thinking using substitution to get a gamma function but after I get an integral Of e^(ax^2+bx^-2), This is I think is the last barrier.So either gamma function, polar coordinates or Cartesian coordinates.All seem horrendous but I’ll see if I can get a solution.

Yep!

There's definitely an easier way of attacking that integral than gamma function/polar coordinates, though.